To get the best deal on Tutoring, call 1-855-666-7440 (Toll Free)

Algebra Word Problems - Page 6

Algebra Word Problems
  • Page 6
 51.  
Bill gave 1 10 th of his salary to the poor people. What is he left with?
a.
$9x 10
b.
$10x
c.
$x 10
d.
$x 2


Solution:

Let $x be the salary of Bill.

The amount he gave to the poor = 1 / 10 × x = x / 10.
[Multiply x with 1 / 10.]

The amount left with Bill = Salary Bill got - The amount he gave to the poor

= x - x / 10
[Substitute the values.]

= 10x / 10 - x / 10
[Multiply and divide the numerator and denominator of the first fraction by 10.]

= 9x / 10
[Subtract the numerators.]


Correct answer : (1)
 52.  
Find Nancy's age, if she was 17, 17 years ago .
a.
34
b.
39
c.
24
d.
44


Solution:

Let x be the present age of Nancy.

The present age of Nancy = Nancy's age 17 years ago + 17
[Write the algebraic expression.]

x = 17 + 17
[Substitute.]

x = 34
[Add.]

So, Nancy is 34 years old.


Correct answer : (1)
 53.  
Paul bought 5 pencils. Find the cost of one pencil, if the cost of ten pencils was $10.
a.
$3
b.
$1
c.
$4
d.
$2


Solution:

Let a be the cost of one pencil.

The cost of one pencil = Cost of ten pencils ÷ number of pencils
[Write an algebraic expression.]

a = 10 ÷ 5
[Substitute.]

a = 2
[Divide 10 with 5.]

So, the cost of one pencil is $2.


Correct answer : (4)
 54.  
Ethan, Sam, Josh, and George went to a movie. Find the cost of one ticket, if they paid $48 for four tickets.
a.
$17
b.
$12
c.
$15
d.
$14


Solution:

Let y be the cost of one ticket.

The cost of one ticket = cost of all the tickets ÷ number of tickets
[Write an Algebraic expression.]

y = 48 ÷ 4
[Substitute.]

y = 12
[Divide 48 with 4.]

So, the cost of one ticket is $12.


Correct answer : (2)
 55.  
Christina visits a food store. She wants to buy 14 burgers. Find the cost of 14 burgers if the cost of one burger is $4.
a.
$56
b.
$61
c.
$51
d.
$66


Solution:

Let b be the cost of 14 burgers.

Cost of 14 burgers = cost of one burger x 14
[Write an algebraic expression.]

b = 4 x 14
[Substitute.]

b = 56
[Multiply.]

So, the cost of 14 burgers is $56.


Correct answer : (1)
 56.  
Edward spends 4 9 of his salary on luxuries. How much is left with him?
a.
4 5 of his salary
b.
5 9 of his salary
c.
1 9 of his salary
d.
4 9 of his salary


Solution:

Let '$p' be the salary of Edward.

The amount he spends on luxuries = 4 / 9 x p = 4p / 9 .
[Multiply p with 4 / 9 .]

The amount left with Edward = Salary Edward gets - the amount he spends on luxuries.

= p - 4p9
[Substitute the values.]

=9p9- 4p9
[Multiply and divide the numerator and denominator of the first fraction by 9.]

= 5p9
[Subtract the numerators.]


Correct answer : (2)
 57.  
Lydia has $68. He buys 2 shirts that cost $13 each. How much is she left with after buying the shirts?
a.
$42
b.
$66
c.
$72
d.
$70


Solution:

Let x be the money she is left with.

Money left = money Lydia has - (cost of one shirt × number of shirts)
[Write an algebraic expression.]

x = $68 - (13 × 2)
[Substitute.]

x = 68 - 26
[Multiply.]

x = 42
[Subtract 26 from 68.]

So, Lydia is left with $42.


Correct answer : (1)
 58.  
William and Tim ran a fundraising campaign. William collected $6 more than Tim. How much did William collect, if Tim collected $12?
a.
$19
b.
$21
c.
$23
d.
$18


Solution:

Let y be the money William collected.

Money collected by William = money collected by Tim + extra dollars collected by William
[Write an Algebraic expression.]

y = 12 + 6
[Substitute.]

y = 18
[Add.]

So, William collected $18.


Correct answer : (4)
 59.  
Jessica buys a box of marbles. The box has 5 dozen marbles. Find the number of marbles in the bag.
a.
48
b.
72
c.
60
d.
66


Solution:

Let x be the number of marbles.

Number of marbles in the bag = number of dozens x 12
[Write an algebraic expression.]

x = 5 x 12
[Convert dozens to number as 1 dozen = 12.]

x = 60
[Multiply.]

Number of marbles in the bag = 60.


Correct answer : (3)
 60.  
How many students are there in Mrs. Zelma's class, if there are 24 boys and 26 girls in the class?
a.
54
b.
48
c.
50
d.
56


Solution:

Let b be the number of students in Mrs. Zelma's class.

Number of students in Mrs. Zelma's class = number of boys + number of girls
[Write an algebraic equation.]

b = 24 + 26
[Substitute.]

b = 50
[Add.]

So, there are 50 students in Mrs. Zelma's class.


Correct answer : (3)

*AP and SAT are registered trademarks of the College Board.