﻿ Scientific Notation Worksheets - Page 10 | Problems & Solutions

# Scientific Notation Worksheets - Page 10

Scientific Notation Worksheets
• Page 10
91.
An hour is equal to 3600 seconds. Identify this number in scientific notation.
 a. 3.6 x 103 b. 3.6 x 102 c. 3.6 x 101 d. None of the above

#### Solution:

A number in scientific notation is the product of two factors. The first factor is a number between 1 and 10 and the second factor is an exponent of 10.

The first factor in the scientific notation of 3600 is 3.6
[Move the decimal point to get a factor greater than or equal to 1 and less than 10.]

The second factor is 103.
[The decimal point is moved 3 places to the left. Use this number as the exponent of 10.]

The representation of one hour in scientific notation is 3.6 x 103 seconds.

92.
The diameter of the Saturn is about 119,300 km. Choose the scientific notation for this number.
 a. 1.193 × 105 b. 0.1193 × 103 c. 1.193 × 106 d. 11.93 × 106

#### Solution:

119,300
[Move the decimal point 5 places to the left, to get a factor greater than or equal to 1 and less than 10.]

= 1.193 × 105
[The exponent of 10 is 5.]

The diameter of the Saturn is about 1.193 × 105 km.

93.
The radius of Uranus is about 25,560 km. Express 25,560 in scientific notation.
 a. 2.556 × 10-4 b. 2.556 × 104 c. 0.2556 × 106 d. 2.556 × 103

94.
Express 3.6 × 108 in standard form.
 a. 360,000,000 b. 36,000,000 c. 0.00000036 d. 3,600,000,000

#### Solution:

3.6 × 108 = 360000000
[A positive exponent indicates a large number. Move the decimal point 8 places to the right.]

= 360,000,000

The standard form of 3.6 × 108 is 360,000,000.

95.
The speed of light is about 1.86 ×105 mi/s. Identify the standard form of this number.
 a. 18,600,000 b. 186,000 c. 1,860,000 d. 0.0000186

96.
The mass of the Earth is about 5.976 x 1024 kg. Write this number in standard form.
 a. 59,760,000,000,000,000,000,000,000 b. 5,976,000,000,000 c. 5,976,000,000,000,000,000,000,000 d. 597,600,000,000,000,000,000,000

#### Solution:

5.976 x 1024 = 5976000000000000000000000
[A positive exponent indicates a large number. Move the decimal point 24 places to the right.]

= 5,976,000,000,000,000,000,000,000

The mass of Earth in the standard form is 5,976,000,000,000,000,000,000,000 kg.

97.
The 1st electron-affinity of chlorine is - 3.64 × 102 kj/mole. Write this number in standard form.
 a. - 364000 kj/mole b. - 364 kj/mole c. - 36400 kj/mole d. - 3640 kj/mole

#### Solution:

- 3.64 x 102 = - 364
[Multiplying by 100 moves the decimal point 2 places to the right.]

The 1st electron-affinity of chlorine in standard form is -364 kj/mole.

98.
Express - 4.4 × 106 in standard form.
 a. - 4,400,000 b. 4,400,000 c. - 44,000,000 d. - 440,000

#### Solution:

- 4.4 x 106 = - 4400000
[Multiplying by 1,000,000 moves the decimal point 6 places to the right.]

The standard form of - 4.4 x 106 is - 4,400,000.

99.
Express 0.004 in scientific notation.
 a. 4 × 10-5 b. 4 × 10-2 c. 4 × 10-3 d. 4 × 10-4

#### Solution:

0.004
[Move the decimal point 3 places right to get a factor greater than or equal to 1 and less than 10.]

= 4 × 10-3
[The exponent of 10 is - 3.]

The scientific notation of 0.004 is 4 × 10-3.

100.
The diameter of a Hydrogen atom is 0.00000001 mm. Express this number in scientific notation.
 a. 1 × 10-8 mm b. 0.1 × 10-7 mm c. 1 × 10-9 mm d. 1 × 108 mm

#### Solution:

A number in scientific notation is the product of two factors. The first factor is a number between 1 and 10 and the second factor is an exponent of 10.

0.00000001
[Move the decimal point 8 places to the right to get a factor greater than or equal to 1 and less than 10.]

= 1 × 0.00000001

= 1 × 10-8
[0.00000001 = 1 / 100000000 = 10-8.]

The diameter of a Hydrogen atom is about 1 × 10-8 mm.