Subtracting Fractions with Unlike Denominators Worksheet

**Page 1**

1.

Simplify the expression: $\frac{2}{5}$ - $\frac{1}{10}$

a. | $\frac{7}{10}$ | ||

b. | $\frac{3}{10}$ | ||

c. | $\frac{3}{5}$ | ||

d. | $\frac{1}{25}$ |

[Original expression.]

The denominators in the two fractions are not the same. So, change the fraction

=

[Multiply the fraction

=

[Subtract the numerators.]

=

Correct answer : (2)

2.

Simplify the expression: $\frac{9}{10}$ - $\frac{1}{2}$

a. | $\frac{3}{5}$ | ||

b. | $\frac{2}{5}$ | ||

c. | $\frac{4}{5}$ | ||

d. | $\frac{1}{5}$ |

[Original expression.]

The denominator of the two fractions are not the same. So, we change the fraction

=

[Multiply the fraction

=

[Simplify.]

=

[Subtract the numerators.]

=

[Simplify.]

Correct answer : (2)

3.

Simplify the expression: $\frac{2}{5}$ - $\frac{1}{10}$

a. | $\frac{3}{5}$ | ||

b. | $\frac{1}{25}$ | ||

c. | $\frac{7}{10}$ | ||

d. | $\frac{3}{10}$ |

[Original expression.]

The denominators in the two fractions are not the same. So, change the fraction

=

[Multiply the fraction

=

[Subtract the numerators.]

=

Correct answer : (4)

4.

Simplify the expression: $\frac{9}{10}$ - $\frac{1}{2}$

a. | $\frac{1}{5}$ | ||

b. | $\frac{2}{5}$ | ||

c. | $\frac{3}{5}$ | ||

d. | $\frac{4}{5}$ |

[Original expression.]

The denominator of the two fractions are not the same. So, we change the fraction

=

[Multiply the fraction

=

[Simplify.]

=

[Subtract the numerators.]

=

[Simplify.]

Correct answer : (2)

5.

Charles and Ed together ate $\frac{5}{6}$ of a cake. If Charles ate $\frac{5}{11}$ of the cake, then how much did Ed eat?

a. | $\frac{5}{6}$ | ||

b. | $\frac{5}{16}$ | ||

c. | $\frac{10}{11}$ | ||

d. | $\frac{25}{66}$ |

=

[Write equivalent fractions using the LCD, 66.]

=

[Since denominators are same, subtract numerators.]

=

Ed ate

Correct answer : (4)

6.

Subtract:

$\frac{12}{5}$

- $\frac{7}{3}$

........

- $\frac{7}{3}$

........

a. | $\frac{1}{15}$ | ||

b. | 15 | ||

c. | $\frac{5}{3}$ | ||

d. | $\frac{3}{5}$ |

Least Common Multiple of 5 and 3 is 15.

The equivalents of

Correct answer : (1)

7.

Simplify: $\frac{11}{5}$ - $\frac{1}{3}$

a. | $\frac{28}{15}$ | ||

b. | $\frac{13}{15}$ | ||

c. | $\frac{15}{28}$ | ||

d. | $\frac{13}{28}$ |

Least Common Multiple of 5 and 3 is 15.

The equivalents of

=

[Group the numerators and subtract.]

Correct answer : (1)

8.

Simplify: $\frac{5}{4}$ - $\frac{1}{3}$

a. | $\frac{11}{12}$ | ||

b. | $\frac{12}{11}$ | ||

c. | $\frac{1}{12}$ | ||

d. | $\frac{1}{11}$ |

Least Common Multiple of 4 and 3 is 12.

The equivalents of

=

[Group the numerators and subtract.]

Correct answer : (1)

9.

It takes $\frac{1}{2}$ hour on foot and $\frac{1}{4}$ hour on a bicycle for Tim to reach his home. How much time does Tim save by going on his bicycle?

a. | 25 minutes | ||

b. | 15 minutes | ||

c. | 20 minutes | ||

d. | 10 minutes |

Time taken by Tim to reach his home on bicycle =

Time saved =

[time taken to reach his home on foot - time taken to reach his home on bicycle.]

[1 hour = 60 minutes,

[1 hour = 60 minutes,

Time saved = 30 minutes - 15 minutes = 15 minutes

[Subtract.]

Tim saves 15 minutes by going on a bicycle.

Correct answer : (2)

10.

Subtract the fraction $\frac{7}{9}$ from the fraction $\frac{5}{3}$.

a. | $\frac{9}{10}$ | ||

b. | 1 | ||

c. | $\frac{9}{11}$ | ||

d. | $\frac{8}{9}$ |

[Original expression.]

The denominators in the two fractions are not the same. So, we change the fraction

=

[Multiply the fraction

[Subtract the numerators.]

=

[Simplify by dividing numerator and denominator with 3.]

Correct answer : (4)